11th Edition Tritak Test Bank

EXAM ELABORATIONS Aug 29, 2025
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Brown and Mulholland’s Drug Calculations 11th Edition Tritak Test Bank

Chapter 01: General Mathematics

Tritak: Brown and Mulholland’s Drug Calculations: Ratio and Proportion Problems for Clinical Practice, 11th Edition

ESSAY

Directions: Solve the following problems.

1. Add and reduce to lowest terms:

ANS:

2. Add:

ANS:

3. Multiply and reduce to lowest terms:

ANS:

4. Multiply and reduce to lowest terms:

ANS:

5. Divide and reduce to lowest terms:

ANS:

6. Divide and reduce to lowest terms:

ANS: 1 / 4

  • Which is greater, ?

ANS:

  • Which is smaller,

ANS:

9. Change to a decimal:

ANS:

0.125

10. Change to a fraction: 0.008

ANS:

  • Which is smaller, 0.125 or 0.25?

ANS:

0.125

  • Which is greater, 0.25 or 0.05?

ANS:

0.25

13. Round to the nearest tenth: 3.124

ANS:

3.1

14. Round to the nearest hundredth: 0.42877

ANS:

0.43

15. Round to the nearest whole number: 5.742

ANS:

6 2 / 4

16. Round to the nearest ten thousandth: 0.576391

ANS:

0.5764

  • Divide 7.35 by 0.25.

ANS:

29.4

  • Multiply 4.25 by 0.2.

ANS:

0.85

  • Find 5% of 75.

ANS:

0.05  75 = 3.75 (10% of 75 is 7.5; 5% would be one half of that)

  • Find 55% of 120.

ANS:

0.55  120 = 66 (a little more than one half of 120)

  • Write as a percentage and as a decimal.

ANS:

10%, 0.1

  • Write 0.05 as a fraction and as a percentage.

ANS:

  • Write 85% as a fraction and as a decimal.

ANS:

  • Change 1 to an improper fraction.

ANS: 3 / 4

  • Change to a whole or mixed number.

ANS:

  • Which is larger, tens or tenths?

ANS:

Tens

  • Write three hundred seventy seven thousandths as a decimal.

ANS:

0.377

  • Make 150 mL of a 50% strength solution. How many mL of the solute will be needed?

ANS:

75 mL

Know Want to Know

  • mL : 2 mL = x mL : 150 mL
  • 2x = 1  150 = 150 x = 75 mL

Proof: 1  150 = 150

2  75 = 150

  • You need to make a 75% Betadine solution for a total of 250 mL. How much Betadine will
  • you need?

ANS:

187.5 mL

Know Want to Know 75 mL : 100 mL = x mL : 250 mL

  • : 4 = x : 250
  • 4x = 3  250 = 750 4x = 750 mL x = 187.5 mL of Betadine. Add 62.50 mL of solution for a total of 250 mL.

Proof: 3  250 = 750

4  187.5 = 750

  • You need to make a 10% solution of hydrogen peroxide for a total of 500 mL. You are using
  • normal saline (NS) as the solvent. How many mL of hydrogen peroxide will you need?

ANS:

  • / 4

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Category: EXAM ELABORATIONS
Added: Aug 29, 2025
Description:

Brown and Mulholland’s Drug Calculations 11th Edition Tritak Test Bank Chapter 01: General Mathematics Tritak: Brown and Mulholland’s Drug Calculations: Ratio and Proportion Problems for Clinic...

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