Henkes Med-math Dosage Calculation Preparation And Administration 9th Edition Buchholz Test Bank Chapter 1, Arithmetic Needed for Dosage
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Basic Care and Comfort
Cognitive Level: Apply
Difficulty: Moderate
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
Integrated Process: Teaching/Learning
Objective: 1, 2
- A patient/client was instructed to drink 25 oz of water within 2 hours but was
only able to drink 15 oz. What portion of the water remained?
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available quantity (25 oz): 10 oz remain. To determine the portion of the water that remains, create a fraction by dividing 10 oz (remaining portion) by 25 oz (total portion). Therefore, 10 divided by 25 = 10/25. To reduce fractions, find the largest number that can be divided evenly into the numerator and the denominator (5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest terms of 2/5.
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Basic Care and Comfort
Cognitive Level: Apply
Difficulty: Moderate
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
A) 2/5
B) 3/5
C) 2/25
D) 25/25
Ans: A
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Integrated Process: Teaching/Learning
Objective: 1, 2
- A patient/client was prescribed 240 mL of Ensure by mouth as a supplement
but consumed only 100 mL. What portion of the Ensure remained?
A) 5/12
B) 7/12
C) 100/240
D) 240/240
Ans: B
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the
total available quantity (240 mL): 140 mL remain. To determine the portion of the Ensure that remains, create a fraction by dividing 140 mL (remaining portion) by 240 mL (total portion). Therefore, 140 divided by 240 = 7/12. To reduce fractions, find the largest number that can be divided evenly into the numerator and the denominator (20); 140 divided by 20 (140/20) = 7; 240/20 = 12. The fraction 140/240 can be reduced to its lowest terms of 7/12.
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Basic Care and Comfort
Cognitive Level: Analyze
Difficulty: Difficult
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
Integrated Process: Communication and Documentation
Objective: 1, 2
- A patient/client consumed 2 oz. of coffee, 2/3 oz. of ice cream, and 1 oz.
of beef broth. What is the total number of ounces consumed that should be documented for the patient/client?
A) 3 3/4
B) 4 5/12
C) 4 2/3
D) 4 4/9
1 4 1
2 2 / 4
Ans: B
Feedback: Add the amount of ounces consumed. First, change any mixed number to
a fraction by multiplying the whole number by the denominator and then adding that total to the numerator. For the coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1 = 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denominators, find the least common denominator (LCD). For 2, 3, and 4, the LCD =
- Rewrite each fraction using the LCD; divide the LCD by the denominator of each
fraction and then multiply that result by the numerator of the fraction. The new fractions to be added are 27/12 (coffee), 8/12 (ice cream), and 18/12 (beef broth).After conversion of the fractions, the numerators are added together and the fraction is reduced to the lowest terms.
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Basic Care and Comfort
Cognitive Level: Analyze
Difficulty: Difficult
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
Integrated Process: Communication and Documentation
Objective: 1, 2
- A coffee cup holds 180 mL. The patient/client drank 2⅓ cups of coffee. How
many milliliters would the nurse document as consumed?
A) 360
B) 420
C) 510
D) 600
Ans: B
Feedback: The coffee cup holds 180 mL. The client drank 2⅓ cups. To estimate the total number of milliliters consumed, multiply 180 7/3 (2⅓). When a mixed number is present, change it to an improper fraction by multiplying the whole number by the
denominator and then adding that total to the numerator: 2 3 = 6 + 1 = 7/3.
Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 × 7 = 420). 3 / 4
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Physiological Adaptation
Cognitive Level: Apply
Difficulty: Moderate
Page and Header: 10, Decimals
Integrated Process: Nursing Process
Objective: 3, 5
- A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How
many kilograms were gained since admission?
A) 0.78
B) 0.88
C) 1.88
D) 1.98
Ans: C
Feedback: To estimate the am
T o E u S n T t B o A f k N il K o S gr E a L m L s E g R a .in C e O d M , subtract weight on admission (48.52) from current weight (50.4 kg) = 1.88 kg (weight gained). To subtract decimals, decimals are stacked lined up. Starting at the far right of the stack, the numbers are subtracted. In the answer, make sure the decimal point lines up exactly with the points above it.
Format: Multiple Choice
Chapter: 1
Client Needs: Physiological Integrity: Physiological Adaptation
Cognitive Level: Apply
Difficulty: Moderate
Page and Header: 10, Decimals
Integrated Process: Teaching/Learning
Objective: 3, 5, 6
- A patient/client's sodium intake for one meal was 0.004 g and 0.152 g. How
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many grams, to the nearest hundredths, of sodium were consumed?