n , period , I * assume ordinarysimple ti t ! ( year ..."> n , period , I * assume ordinarysimple ti t ! ( year ..."> n , period , I * assume ordinarysimple ti t ! ( year ..."> n , period , I * assume ordinarysimple ti t ! ( year ..." /> basisofinterestisalwaystheinitial - basisofinterestisalwaystheinitial
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basisofinterestisalwaystheinitial

EXAM ELABORATIONS Aug 27, 2025
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Engineering Economy 1 / 2

-

SIMPLEINTEREST

- "¥ basisofinterestisalwaystheinitial amount Solh

:69

- O

31 100

°i 2 3n F=p ( It rn ) ll l 7 # ... I > n , period , I * assume ordinarysimple ti t !( year , month , etc ) pN # / interest ,unless specified l l l l = F - D

where: u

v ' ' l l I = Prn * eco .o, )f Aassume annualinterest P I l l l P - - 0.97F rate , unless specified PtPrl llD - - 0.03ft l l TI Ptprcz ) l l netinterest

:

trI Ptprl's 1 , I ' = I - T I = Prn + Ptprn - -F

0.03¥

:

0.97 #4) ( ¥0) r - -

0.1614

or

16.14%

*2TypesofsimpleInterest * • Ordinary "¥ assumes thatthere are 30 days )month or 360days in a year , calledthe " banker 'srule " Solh

:

• Exact I ' - - I - T "¥ assumes theexactdays in a year890.36 i I -

0.2015

wk is365 (regular) and366 (leapyear ) I - -

1112.95

SAMPLEPROBLEMS

:

I = Prn

1112.95--110000(

r )(}÷o) r

:

0.1175

I

11.75%

Solh

:

From May1,2002 toMay1,2005 = 3 ( 360 ) FromMay I , 2005 toAug .

1,2005

:

90 1170 days I

:

Prn =

250006.08

)(

'317600

) I - - 6,500 Solh

:

May I ,

20021365

May1,2003 May

1,20041366

May

1,20051365

May 131 ) August1,2005 !Junko) July( 31 ) 1188days I - - Prn '

25.0001000

)( "8386¥ ) I

:

6,504.11

  • / 2

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Category: EXAM ELABORATIONS
Added: Aug 27, 2025
Description:

Engineering Economy - SIMPLEINTEREST - "¥ basisofinterestisalwaystheinitial amount Solh : 69 - O 31 100 °i 2 3 n F=p ( It rn ) ll l # ... I > n , period , I * assume ordinarysimple ti t ! ( year ...

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