FROM SAMPLE TEST: - FROM SAMPLE TEST: 1. A 125 mL sample of orange ...

EXAM ELABORATIONS Sep 4, 2025
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General Chemistry I - Exam 2: Pitt

FROM SAMPLE TEST:

  • A 125 mL sample of orange juice was titrated using a redox reaction to the
  • equivalence point with the addition of 7.6 mL of a 0.025 M iodine (I₂) solution. What is the concentration of vitamin C (C₆H₈O₆) in this sample?

Reaction:

C₆H₈O₆ (aq) + I₂ (aq) → C₆H₆O₆ (aq) + 2I⁻ (aq) + 2H⁺ (aq)

Options:

  • 30 mM
  • 15 mM
  • 19 mM
  • 0.30 mM
  • 0.15 mM

Correct Answer: E

  • How many moles are there in 1.50 grams of ethanol (C₂H₅OH)?

Options:

  • 0.0145 mol
  • 0.0326 mol
  • 30.7 mol
  • 69.0 mol

Correct Answer: B

3. Given the reaction:

Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂ How many moles of Ag will be produced from 46.0 grams of Cu?

Correct Answer: 1.45 moles

4. Given the reaction:

  • Fe + 3 O₂ → 2 Fe₂O₃ 1 / 3

How many moles of Fe₂O₃ will be produced from 27 grams of Fe?

Correct Answer: 0.242 moles

5. Given the reaction:

Zn + 2 HCl → ZnCl₂ + H₂ How many moles of ZnCl₂ will be produced from 55.0 grams of Zn?

Correct Answer: 0.841 moles

  • What is a limiting reactant?

Correct Answer: The reactant that has the smallest stoichiometric amount in a

reactant mixture and consequently limits the amount of product in a chemical reaction.

7. Given the reaction:

NaCl + AgNO₃ → AgCl + NaNO₃ If 5.00 grams of NaCl and 103 grams of AgNO₃ are used, which compound is the limiting reactant?

Correct Answer: NaCl

8. Given the reaction:

Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂ How many grams of Ag will be produced from 5.00 grams of Cu and 1.00 gram of AgNO₃?

Correct Answer: 0.640 grams

9. Given the reaction:

CH₄ + 2 O₂ → CO₂ + 2 H₂O

How many grams of CO₂ will be produced from 15.0 grams of CH₄ and 114 grams of O₂?

Correct Answer: 41.2 grams

10. Given the reaction:

N₂ + 3 H₂ → 2 NH₃

This reaction gave an actual yield of 98.67 grams of NH₃, from 85.90 grams of N₂ and 21.66 grams of H₂. What is the percent yield of NH₃?

Correct Answer: 94.49% 2 / 3

  • What is molarity (M)?

Correct Answer: Amount of Solute (in mols) / Volume of Solution (in Liters)

  • A 0.200 L cup of tea contains 3.765 grams of sucrose (molar mass = 342.3
  • g/mol). What is the molarity of sucrose in the tea?

Correct Answer: 0.0550 M

  • A 0.250 L sample of seawater contains 77.4 grams of NaCl (molar mass =
  • 58.44 g/mol). What is the molarity of NaCl in the seawater?

Correct Answer: 5.30 M

  • A 2.00 M hydrochloric acid solution is prepared with a total volume of 0.350
  • L (molar mass HCl = 36.46 g/mol). What mass of HCl is needed?

Correct Answer: 25.5 grams

  • A 0.839 M acetic acid solution is prepared with a total volume of 500 mL
  • (molar mass = 60.05 g/mol). What mass of acetic acid is needed?

Correct Answer: 25.2 grams

  • A 0.385 M MnSO₄ solution is prepared using 57.0 grams of MnSO₄ (molar
  • mass = 151.0 g/mol). What is the volume of the solution?

Correct Answer: 0.980 L

  • Suppose a laboratory procedure calls for 3.00 L of 0.500 M CaCl₂ solution,
  • but only a 10 M CaCl₂ solution is available. What volume of the 10 M solution must be diluted?

Correct Answer: 0.15 L

  • What's the formula for dilution?

Correct Answer: M₁ × V₁ = M₂ × V₂

  • If you have 0.200 L of a 15 M NaOH solution but need a 3 M NaOH solution,
  • to what volume should you dilute it?

Correct Answer: 1 L

  • A procedure calls for 500 mL of 0.450 M NaCl, but only a 5 M NaCl solution
  • is available. What volume of the 5 M solution must be diluted?

Correct Answer: 45 mL

  • / 3

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Category: EXAM ELABORATIONS
Added: Sep 4, 2025
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General Chemistry I - Exam 2: Pitt FROM SAMPLE TEST: 1. A 125 mL sample of orange juice was titrated using a redox reaction to the equivalence point with the addition of 7.6 mL of a 0.025 M iodine ...

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