MAT 136 Exam 1 AND 2 Questions and Answers - Southern New Hampshire University

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MAT 136 Exam 1 AND 2 Questions and Answers - Southern New Hampshire University

Question

√ 2⋅9

• Cancel the common factors of 18 and 16 which would be 2

2⋅8 √ 9

• Rewrite

8

√9

• as

√8

3

• The squareroot of 9 = 3, factor 4 out of 8

√4(2)

3

• The squareroot of 4 = 2, remove 2 from radical

2√2 (

3 ) ⋅ (

√2 ) - Multiply togther and simplify

2√2 √2

(3⋅√2)

2(√2)

2

(3⋅√2)

n x x 1

• use √a = a n to rewrite √2 as 2 2 and simplify 1

2

2(2 2 )

(3√2)

2⋅2

(3√2)

4

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Ungraded Grade: 0/1.0

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Question

Total grade: 1.0×1/2 + 0.0×1/2 = 50% + 0%

Feedback:

√ 18 = √ 2⋅9 Factor perfect squares from the radicand.16 16 = 3 √2 Simplify.4

Q2 0/0.0

View Original Response Unfiltered Response Solve for x.

• (x + 3) − 37 = x + 6

Enter the exact answer.

x = Your response Correct response

• 5

Auto graded Grade: 1/1.0

Show your work and explain, in your own words, how you arrived at your answer. Answers with no relevant explanations may receive reduced or no credit.

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Question

• (x + 3) − 37 - Simplify the left side of the equaiton
• x + 18 − 37 - 6*x and 6*3
• x − 19 = x + 6
• x − 19 − x = 6 - move x to the left side of the equation by subtracting from both sides
• x − 19 = 6 - subtract x from 6x
• x = 6 + 19 - Move 19 to the right side of the equation by adding 19 to both sides
• x = 25 - Add 6+19

x = 25

• Move 5 to the right side by dividing by 5

5 x = 5

Ungraded Grade: 0/1.0

Total grade: 1.0×1/2 + 0.0×1/2 = 50% + 0%

Feedback:

Apply standard algebraic properties.

• (x + 3) − 37 = x + 6

6x + 18 − 37 = x + 6 6x − 19 = x + 6 5x = 25 x = 25 5 x = 5

Apply the distributive property.Combine like terms.Place x- terms on one side and simplify.Multiply both sides by 1 , the reciprocal of 5.5

Q3 0/0.0

View Original Response Unfiltered Response

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